- Joined
- Jan 23, 2016
- Messages
- 12
Hey everyone! I'm building a DIY Kiln that I plan on using for a wax burn-out oven for casting. I will be casting sword/knife parts. I stumbled on a few great DIY heat-treating oven resources here and on youtube (Red Beard Ops and DC Knives)
I would love some "extra eyes" of my plans and calculation, while still in paper form, in hopes to not end up burning my house down.
Basic Oven Specs (I think?)
Interior Oven Space - 15.5" x 9" x 9" = 1395 cubic inches / 0.8062 cubic feet
Watts per Cubic ft - 4339.3
These are my calculation based on the Ohms Calculator Spreadsheet DC Knives provided.
Voltage - 240
Desired - W 3500 (This number is arbitrary for me; I just picked something that gave me the desired length of stretched coil)
Number of Elements - 2
Amperers - 14.583 (I have plenty of room for this number to increase. I'm putting in a new 100amp service panel in my shop and can honestly put in whatever size breaker I want, so if you guys have any better suggestions, I'm all ears.)
Ohms - 32.914
Coil Diameter - 0.375
Length of wire 16awg
Coil length - 6'
Stretched Coil length - 12'
I know this may be very straightforward, but I would rather ask than burn something down.
1. When I input the number of elements being 2, that refers to me using two different heating elements running in parallel, correct?
2. If it says my "stretched coil length" should be 12', does that mean I need to split the 12' in half and have two elements that are 6' long, each with 16.457ohms (32.914/2)? OR Do I need two coils that are both 12' long with ohms of 32.914 each?


I hope that makes sense. I appreciate your help.
I would love some "extra eyes" of my plans and calculation, while still in paper form, in hopes to not end up burning my house down.
Basic Oven Specs (I think?)
Interior Oven Space - 15.5" x 9" x 9" = 1395 cubic inches / 0.8062 cubic feet
Watts per Cubic ft - 4339.3
These are my calculation based on the Ohms Calculator Spreadsheet DC Knives provided.
Voltage - 240
Desired - W 3500 (This number is arbitrary for me; I just picked something that gave me the desired length of stretched coil)
Number of Elements - 2
Amperers - 14.583 (I have plenty of room for this number to increase. I'm putting in a new 100amp service panel in my shop and can honestly put in whatever size breaker I want, so if you guys have any better suggestions, I'm all ears.)
Ohms - 32.914
Coil Diameter - 0.375
Length of wire 16awg
Coil length - 6'
Stretched Coil length - 12'
I know this may be very straightforward, but I would rather ask than burn something down.
1. When I input the number of elements being 2, that refers to me using two different heating elements running in parallel, correct?
2. If it says my "stretched coil length" should be 12', does that mean I need to split the 12' in half and have two elements that are 6' long, each with 16.457ohms (32.914/2)? OR Do I need two coils that are both 12' long with ohms of 32.914 each?


I hope that makes sense. I appreciate your help.