<font face="Verdana, Arial" size="2">Originally posted by Cliff Stamp:
I have a 440A fillet blade in a salt water solution now for a week and it shows only a slight surface rusting in a few areas that would wipe off with a cloth. The piece of BG-42 I have in with it is completely covered in deep black and orange oxide. Most high end cutlery stainless blades do not leave a significant amount of free Cr in the steel so their corrosion resistance is low. Doesn't do the steel any good corrosion wise if the Cr isn't free, regardless of the percentage in the mix.
-Cliff
</font>
Very interesting ... especially the more extensive pitting damage to "stainless" stuff vs. INFI. Just shows me how much I have to learn.
The "free chrome" thing ... would be interesting to soak 440A and 440C from say the same mfg... since ostensibly both 440's would have the same starting chrome content if the mfg got them from the same source, i.e. 16% to 18% chrome.
Since 440A has 0.65% to 0.75% carbon, and 440C has 0.95% to 1.2% carbon, this would suggest that 440C will have more chrome carbides in the matrix, leaving less chromium around to oxidize into chrome oxide, said oxide layer being what our plant metallurgist tells me is primarily responsible for general corrosion resistance of high chrome alloys.
Crucible indicates that 420V exceeds the corrosion resistance of 440V, this despite starting chrome in 420V of ~14% and starting chrome in 440V of 17%. May be a similar story... 420V must use it's carbon preferentially to bind up with Vanadium (9%)in making Vanadium carbides, leaving more free chrome around to form chrome oxide vs. what happens in 440V with "only" 5.5% Vanadium. If this is not the case, I am again confused and in search of something that explains the "truth" a bit closer.
Similarly, Crucible gives their regular 420 "Prem" (similar to 420Mod & 420HC) about double the corrosion resistance rating of 440C. Regular 420M only has 0.4% carbon and 12%-14% chrome... but apparently plenty of chrome is around for chromium oxide vs 440C, even though 440C starts at 16-18% chrome.
We see alloy compositions in weight percent I believe. But molecularly, this stuff binds up in different ratios I'm sure... would be nice to see what relative ratios that chrome, moly, & vanadium bind up with carbon, converted to weight %. Better still, alloy compositions given in terms like:
5% free chrome
7% chrome carbide
3% vanadium carbide
4% moly carbide
By the way, chrome only oxidizes (or "rusts") to chromium oxide on the surface. That chrome oxide layer can be worn off by use, but reforms fairly quickly if free chrome is around. During alloy formation, Manganese and Silicon are two of the elements used as an oxygen scavengers, i.e. they help remove oxygen from molten liquid, how? I dunno yet... do they grab oxygen and oxidize in molten state? Or do they cause it to off-gas somehow?
[This message has been edited by rdangerer (edited 05-28-2001).]